Lecture 02: Urogenital System I & II

HoyaDocs — Repro Block | USMLE Step 1 Preparation

Lecture 02 — Overview

Urogenital System I & II · HoyaDocs Repro Block

Page Summaries

🫘 Kidney Development
Intermediate mesoderm origins
Pronephros · Mesonephros · Metanephros · Ureteric bud · Reciprocal induction · Nephron formation · Ascent & rotation
Practice Qs: 1–3
🚽 Bladder & Duct Derivatives
Cloaca · Urogenital sinus · Bladder + trigone
Wolffian (SEED) vs. Müllerian ducts · Urachus · Derivative master table
Practice Qs: 4–6
⚧ Genital Differentiation
Bipotential gonad · SRY · Sertoli/MIS · Leydig/testosterone · 5α-reductase/DHT · Bipotential external genitalia
Practice Qs: 7–9
⚠️ Urinary & Genital Anomalies
Potter sequence · MCDK · Horseshoe · Pelvic kidney · Ureter anomalies · Testicular descent · Cryptorchidism · Hypospadias/Epispadias
Practice Qs: 10–13
🧬 Disorders of Sex Development
Adrenal steroidogenesis · CAH (21-OH · 11β-OH · 17α-OH · 3β-HSD) · Androgen Insensitivity (CAIS/PAIS) · 5α-reductase deficiency · 46,XX virilization · Klinefelter (47,XXY) · Turner (45,XO)
Practice Qs: 14–18

Official Learning Objectives Map

1 Become introduced to urology — foundational anatomy and development of the kidney, ureters, and bladder Urology Primer ▼
3 Relate information from this module to information that will be useful on the boards, on the wards, and in general life — chromosomal DSDs, associated syndromes, and clinical integrations Integration ▼

LO 1 — Kidney Development

Pronephros → Mesonephros → Metanephros · Ureteric Bud · Ascent · HoyaDocs Repro Block

Learning Objectives Covered
  • LO 1: Understand the sequential origin of the three embryologic "kidney" systems and the tissues from which they arise
  • LO 2: Correlate the reciprocal induction between the ureteric bud and metanephric blastema with normal kidney and collecting-system architecture
  • LO 3: Relate kidney ascent, rotation, and blood-supply turnover to future anatomical/clinical findings on the boards and the wards

🧠 Testing Your Understanding!

Testing Your Understanding — LO 1, Question 1

A researcher genetically ablates the metanephric blastema in a mouse embryo at gestational day equivalent to human week 5 while leaving the ureteric bud intact. Predict the kidney phenotype at term, and explain why this outcome occurs mechanistically.

Consider: reciprocal induction, GDNF signaling, the role of metanephric mesoderm in nephron formation, what the ureteric bud can build on its own

✓ Answer: Bilateral renal agenesis (Potter sequence phenotype)

The metanephric blastema is the source of GDNF, which induces the mesonephric duct to sprout a ureteric bud; reciprocally, it also receives signals (WNT9B, FGF2) from the bud to condense into nephrons. Without the blastema, the bud has no target and no inductive partner — there is no collecting system branching and no nephron formation, so no functional kidney develops. Because amniotic fluid after the second trimester comes from fetal urine, bilateral absence leads to oligohydramnios, fetal compression (flat facies, limb deformities), and pulmonary hypoplasia — the Potter sequence. Consider: how would a unilateral defect differ? (Contralateral compensatory hypertrophy; usually viable.)

Testing Your Understanding — LO 1, Question 2

On fetal ultrasound at 20 weeks, a kidney is noted to sit low in the pelvis. The adrenal gland on the same side appears in its normal superior position. Explain this anatomical dissociation using the embryology of kidney ascent.

Consider: where the kidneys begin, where the adrenals develop, timing of ascent, fate of old blood supply

✓ Answer: The kidney and adrenal have separate origins, so a failure of kidney ascent does not carry the adrenal along.

The metanephros forms in the pelvis and ascends from weeks 6–9, rotating medially and progressively picking up new arterial branches from the aorta as older iliac vessels involute. The adrenal glands develop independently from two sources — the cortex from mesoderm and the medulla from neural-crest ectoderm — near the diaphragm. They do not migrate with the kidney. If the metanephros fails to ascend, the adrenal still takes its normal sub-diaphragmatic position because it was never linked. This explains why a pelvic kidney is typically asymptomatic and incidentally detected. Consider: what blood supply would a pelvic kidney have? (Often variant branches of the common iliac, representing persistence of the kidney's original fetal vessels.)

LO 2 — Bladder, Urethra & Duct Derivatives

Cloaca → Urogenital Sinus · Wolffian vs. Müllerian Duct Fates · HoyaDocs Repro Block

Learning Objectives Covered
  • LO 1: Identify the urinary tract derivatives of the cloaca and urogenital sinus
  • LO 2: Correlate Wolffian and Müllerian duct fates with male and female reproductive anatomy
  • LO 3: Apply the UG-tract derivatives table to board-style stems and ward anatomy questions

🧠 Testing Your Understanding!

Testing Your Understanding — LO 2, Question 1

A 16-year-old phenotypic female presents with primary amenorrhea. Pelvic imaging shows a uterus that appears split into two horns, and her right kidney is absent. Use embryology to explain why these two findings go together.

Consider: Müllerian duct fusion, ureteric bud origin, the shared induction signals between Wolffian and paramesonephric ducts

✓ Answer: Bicornuate uterus + unilateral renal agenesis = joint failure of the paramesonephric and ureteric bud/mesonephric duct systems.

The two paramesonephric (Müllerian) ducts fuse inferiorly to form the uterus, cervix, and upper 2/3 of the vagina — partial fusion produces a bicornuate uterus. The Müllerian ducts rely on the mesonephric duct as a physical scaffold to guide their descent; this is why paramesonephric and mesonephric development are tightly linked. Because the ureteric bud sprouts from the caudal mesonephric duct, a unilateral Wolffian disruption can simultaneously cause failed ureteric bud formation — producing ipsilateral renal agenesis. Always order a renal ultrasound on any patient with a Müllerian anomaly. Consider: if the defect were bilateral, what would you expect? (Bilateral renal agenesis = Potter sequence.)

Testing Your Understanding — LO 2, Question 2

A newborn boy undergoes exploratory surgery for bilateral non-palpable testes. The surgeon discovers a small uterus and two fallopian tubes adjacent to the inguinal canals. Chromosomal analysis is 46,XY; testosterone, DHT, and gonadotropin levels are all normal. What embryologic mechanism explains this finding?

Consider: Sertoli cells, MIS/AMH, androgen axis, paramesonephric duct regression

✓ Answer: Persistent Müllerian Duct Syndrome — defective MIS production or MIS-receptor signaling by Sertoli cells.

In normal male development, Sertoli cells secrete Müllerian Inhibiting Substance (MIS/AMH), which triggers regression of the paramesonephric ducts beginning at week 7–8. Leydig cells concurrently produce testosterone, which drives Wolffian duct development into SEED structures. Because this patient has normal testosterone and normal external male genitalia but retained Müllerian derivatives, the defect is specifically in the MIS axis — either a missense mutation in the AMH gene (MIS deficiency) or in the MIS type II receptor. The retained Müllerian structures often tether the testes intra-abdominally, explaining the associated cryptorchidism. Consider: how does this differ from CAIS? (CAIS has an androgen receptor defect, but MIS is normal — so Müllerian structures are absent.)

LO 3 — Genital Differentiation & External Genitalia

SRY → Gonads → Hormones → External Phenotype · HoyaDocs Repro Block

Learning Objectives Covered
  • LO 1: Understand the hormonal and genetic cascade that converts bipotential gonads and external structures into male or female anatomy
  • LO 2: Correlate SRY, testosterone, DHT, and MIS signaling with specific adult internal and external structures
  • LO 3: Apply the genital-differentiation cascade to clinical scenarios involving intersex development

🧠 Testing Your Understanding!

Testing Your Understanding — LO 3, Question 1

A 14-year-old with 46,XY karyotype presents with primary amenorrhea. On exam, breast development is Tanner IV, pubic and axillary hair are sparse, and the vagina is short and blind-ending. Uterus and fallopian tubes are absent on imaging; bilateral inguinal masses are palpable. Map this phenotype to the embryology: which hormones are working, which are not?

Consider: SRY, MIS, testosterone, DHT, androgen receptor, aromatase

✓ Answer: Complete Androgen Insensitivity Syndrome (CAIS) — X-linked androgen receptor mutation.

The SRY gene is active → testes form → both Sertoli (MIS works → Müllerian regression → no uterus/upper vagina) and Leydig (testosterone normal or high) are functional. However, the androgen receptor is nonfunctional, so neither testosterone nor DHT can signal in target tissues: Wolffian ducts regress (no SEED), external genitalia default to female (no DHT effect), and body hair fails at puberty. Aromatase converts circulating testosterone to estradiol, driving breast development at puberty. The "inguinal masses" are the undescended testes — they must be removed after puberty due to malignancy risk. Consider: how would partial androgen insensitivity differ? (Ambiguous external genitalia; some virilization at puberty.)

Testing Your Understanding — LO 3, Question 2

A 46,XY fetus has a selective block that prevents conversion of testosterone to DHT. Predict the internal ductal anatomy and external genitalia at birth, and explain what changes at puberty and why.

Consider: Wolffian duct ligand, external genitalia ligand, pubertal testosterone surge, source of virilization

✓ Answer: 5α-reductase deficiency — normal internal male ducts, but external genitalia appear female at birth; virilize at puberty.

The Wolffian duct is testosterone-dependent, so internal male ducts (SEED) are preserved. Sertoli cells still make MIS, so Müllerian ducts regress as expected. However, the external genitalia and prostate require DHT — without it, the genital tubercle doesn't elongate, the urogenital folds don't fuse, and the labioscrotal swellings don't close. Phenotype at birth: ambiguous or frankly female external genitalia, often with penoscrotal hypospadias, a blind-ending vagina, and labial fusion. At puberty, the massive testosterone surge can directly drive some virilization (deepening voice, muscle mass, phallic growth) via high testosterone-to-androgen-receptor signaling in tissues where T alone is sufficient. Lab finding: high testosterone-to-DHT ratio. Consider: how would this differ from CAIS? (In CAIS, the androgen receptor itself is broken, so puberty cannot drive virilization.)

LO 4 — Urinary & Genital Anomalies

Renal malformations · Ureter defects · Testicular descent · Hypospadias/Epispadias · HoyaDocs Repro Block

Learning Objectives Covered
  • LO 1: Recognize common congenital urogenital anomalies and their clinical presentations
  • LO 2: Correlate each anomaly with a specific developmental error (ureteric bud, kidney ascent, urethral fold fusion, gubernaculum)
  • LO 3: Apply this to board-style vignettes and ward imaging findings

🧠 Testing Your Understanding!

Testing Your Understanding — LO 4, Question 1

A 4-year-old girl is referred for evaluation of "always being a little wet." Her mother reports that she voids normally every 2–3 hours, but there is continuous dribbling of urine between voids. Renal ultrasound shows a duplex collecting system on the right. Explain the embryologic mechanism and predict the exact anatomic location of the abnormal ureter.

Consider: ureteric bud absorption into the bladder, upper vs. lower pole ureter in duplex kidneys, location of the external urethral sphincter in females

✓ Answer: Ectopic ureter draining the upper pole of a duplex kidney, inserting below the external urethral sphincter.

With a duplex kidney, two ureters exist. By the Weigert-Meyer rule, the upper-pole ureter inserts inferiorly and medially (often ectopically) while the lower-pole ureter inserts normally at the trigone. An ectopic ureter results from abnormal absorption of the mesonephric duct into the bladder wall — the ectopic opening ends up outside the normal trigone. In females, this is often distal to the external urethral sphincter (urethra, vagina, or vestibule), which bypasses voluntary continence → constant dribbling despite normal voiding through the other ureter. In males, ectopic ureters open above the sphincter, so continuous incontinence doesn't occur. Consider: what additional finding often accompanies this? (Ureterocele of the upper-pole ureter with a "cobra-head" sign on imaging.)

Testing Your Understanding — LO 4, Question 2

A newborn boy is noted to have a small scrotum with only a left palpable testis, and a urethral opening visible on the ventral surface of the penis halfway down the shaft. Map the embryology: which developmental event produced each finding, and what single hormonal axis is implicated in both?

Consider: testicular descent, gubernaculum, DHT action on external genitalia, urethral fold fusion

✓ Answer: Cryptorchidism + hypospadias — both are DHT/androgen-dependent.

Testicular descent through the inguinal canal is guided by the gubernaculum and requires normal androgen signaling (particularly in the second descent phase). Hypospadias results from failure of the urogenital (urethral) folds to fuse along the ventral penis — a process driven by DHT. When both defects co-occur, suspect either a mild DSD (partial androgen insensitivity, 5α-reductase deficiency) or a maternal/placental cause of relative androgen deficiency. Important management pearls: (1) do NOT circumcise a newborn with hypospadias — the foreskin is reserved for urethroplasty; (2) if testes are non-palpable bilaterally, order a karyotype to rule out a virilized 46,XX with CAH — giving testosterone to a virilized female could cause harm. Consider: what is the most common histologic finding in a retained abdominal testis after age 10? (Seminoma precursor, GCNIS → orchidopexy before age 1.)

LO 5 — Disorders of Sex Development (DSDs)

CAH · Androgen Insensitivity · 5α-Reductase · Klinefelter · Turner · HoyaDocs Repro Block

Learning Objectives Covered
  • LO 1: Understand the adrenal steroidogenesis axis and how enzyme blocks shunt precursors into androgens
  • LO 2: Correlate each DSD with karyotype, hormonal profile, internal and external phenotype
  • LO 3: Distinguish and apply chromosomal DSDs (Klinefelter, Turner) from hormonal DSDs on boards-style vignettes

🧠 Testing Your Understanding!

Testing Your Understanding — LO 5, Question 1

A 2-week-old 46,XX infant with ambiguous genitalia presents with vomiting, poor feeding, hyponatremia (122 mEq/L), hyperkalemia (6.8 mEq/L), and hypotension. Serum 17-hydroxyprogesterone is markedly elevated. Walk through the pathophysiology from enzyme block to salt-wasting crisis, and explain why the external genitalia are virilized.

Consider: adrenal zones, steroidogenesis pathways, precursor shunting, fetal adrenal androgen exposure timing

✓ Answer: Classic salt-wasting 21-hydroxylase deficiency (21-OH CAH).

The 21-hydroxylase block prevents conversion of progesterone → 11-deoxycorticosterone (mineralocorticoid pathway) and 17-OH progesterone → 11-deoxycortisol (glucocorticoid pathway). Result: ↓ aldosterone (can't reabsorb Na, excrete K → hyponatremia, hyperkalemia, metabolic acidosis, hypotension) and ↓ cortisol (↓ negative feedback on ACTH → adrenal hyperplasia). The accumulated 17-OH progesterone is diverted into the androgen pathway (via 17,20-lyase → DHEA → androstenedione → testosterone → DHT) beginning early in gestation. First-trimester DHT exposure causes labioscrotal fusion and clitoromegaly — the 46,XX female is virilized. Management: hydrocortisone (replaces cortisol + suppresses ACTH), fludrocortisone (replaces mineralocorticoid), IV saline/glucose, and delayed feminizing genitoplasty. Consider: why would 46,XY infants appear normal at birth and present later with only salt-wasting? (External genitalia are already male by DHT; shunt-related androgens don't change phenotype.)

Testing Your Understanding — LO 5, Question 2

A 14-year-old girl presents with short stature, primary amenorrhea, and no breast development. Exam reveals a webbed neck, shield chest, and wide carrying angle. Labs show FSH 95 mIU/mL, LH 40 mIU/mL, estradiol <10 pg/mL. Echocardiogram shows a bicuspid aortic valve with mild coarctation; renal ultrasound reveals a horseshoe kidney. Name the diagnosis and explain the embryologic and cytogenetic mechanism linking all findings.

Consider: ovarian follicle atresia, SHOX haploinsufficiency, neural crest / cardiac development, kidney fusion embryology

✓ Answer: Turner syndrome (45,XO) — haploinsufficiency of X-linked genes produces multi-system findings.

In Turner syndrome, oocytes undergo accelerated atresia in utero, leaving streak gonads that cannot produce estrogen → failure of pubertal breast development and primary amenorrhea; gonadotropins (FSH > LH) are dramatically elevated because of absent estrogen feedback. SHOX gene haploinsufficiency on Xp is responsible for short stature and skeletal abnormalities (short metacarpals, cubitus valgus). Defective cervical lymphatic development causes intrauterine cystic hygroma, producing the webbed neck and pedal lymphedema. Abnormal neural-crest contribution to the cardiac outflow tract accounts for the bicuspid aortic valve (most common) and coarctation of the aorta. The horseshoe kidney reflects abnormal midline fusion of the metanephric blastemas, blocked during ascent by the IMA. Management: growth hormone for short stature; estrogen replacement to induce puberty and maintain bone density; cardiac surveillance; fertility via donor oocytes/ART. Consider: why is life-long cardiac imaging critical? (↑ Risk of aortic dissection, especially during pregnancy.)

Practice Questions

Lecture 02 — Urogenital System I & II · HoyaDocs Repro Block

LO 1 — Kidney Development (Q1–Q3)

Question 1

A fetal autopsy reveals small, non-functional kidneys with markedly hypoplastic collecting systems and a few dysmorphic nephrons. Genetic analysis identifies a homozygous loss-of-function mutation in GDNF. Which of the following developmental interactions failed first in this embryo?

A. Migration of primordial germ cells into the genital ridge

B. Signaling from the metanephric blastema to the mesonephric duct to induce the ureteric bud

C. Fusion of the urorectal septum with the cloacal membrane

D. Secretion of Müllerian Inhibiting Substance by Sertoli cells

E. Involution of transient fetal vessels during kidney ascent

✓ Correct: B — GDNF from the metanephric blastema induces ureteric bud outgrowth from the mesonephric duct.

GDNF (glial-derived neurotrophic factor) is made by the metanephric mesoderm and binds RET on the mesonephric duct to trigger ureteric bud budding — the first step in reciprocal induction. Without GDNF, no bud forms; without a bud, no collecting system branches and no inductive signals (WNT9B, FGF2) reach the blastema, so nephron differentiation is abortive. A (PGC migration) is distinct from renal development. C is the cloaca-split step. D is Sertoli/MIS signaling, unrelated to renal dev. E (vessel turnover) is an ascent problem, later. Tie-in: bilateral failure of this axis → renal agenesis → Potter sequence.

Question 2

A newborn is found to have a horseshoe kidney on prenatal ultrasound. The radiologist notes the kidney is located more caudally than expected. Which of the following embryological structures is most directly responsible for halting the ascent of this fused kidney?

A. Superior mesenteric artery

B. Celiac trunk

C. Inferior mesenteric artery

D. Renal arteries at L1

E. Common iliac arteries

✓ Correct: C — The inferior mesenteric artery (IMA) traps the horseshoe isthmus during ascent.

Normally the metanephros ascends from the pelvis to L1–L2, rotating medially and picking up new arterial branches from the aorta as iliac vessels regress. In a horseshoe kidney, the fused lower-pole isthmus gets caught on the IMA at L3, so the kidney sits low in the abdomen. It is not the SMA or celiac trunk (those are more cranial and above the ascent endpoint). Clinical pearls: ↑ UTIs, stones, hydronephrosis, Wilms tumor, and classic association with Turner syndrome.

Question 3

During the 7th week of gestation, a developing kidney is examined. Cells derived from the metanephric blastema are labeled with a fluorescent tracer. Which of the following adult structures would be labeled?

A. Major and minor calyces

B. Renal pelvis

C. Collecting ducts

D. Proximal convoluted tubule and glomerulus

E. Ureter

✓ Correct: D — The nephron (Bowman's capsule + glomerulus + PCT + LOH + DCT) derives from the metanephric blastema.

Embryology split to memorize: metanephric blastema → nephron (Bowman's, glomerulus, PCT, LOH, DCT); ureteric bud → collecting system (collecting ducts, minor calyces, major calyces, renal pelvis, ureter). Choices A, B, C, and E are all ureteric-bud derivatives. A common Step 1 trap is confusing which structure makes what — particularly the collecting ducts, which feel like "the nephron's endpoint" but are actually ureteric-bud tissue.

LO 2 — Bladder & Duct Derivatives (Q4–Q6)

Question 4

A 48-year-old man presents with gross hematuria. Cystoscopy reveals a 2-cm tumor at the dome of the bladder in the midline. Histology shows mucin-producing glandular cells (adenocarcinoma). Which embryologic remnant most likely gave rise to this tumor?

A. Wolffian duct

B. Paramesonephric (Müllerian) duct

C. Urachus (allantois)

D. Cloacal membrane

E. Nephrogenic cord

✓ Correct: C — Urachal (allantoic) remnant at the bladder dome gives rise to adenocarcinoma.

The allantois connects the primitive bladder apex to the umbilicus; it normally obliterates to form the median umbilical ligament (urachus). Persistent segments can become cysts or sinuses and, rarely, undergo malignant transformation into adenocarcinoma at the bladder dome — distinct from the more common transitional cell carcinoma (urothelial) which arises from endodermal urothelium and usually occurs on the lateral walls or trigone. Wolffian duct (A) gives the trigone but not the dome. Müllerian (B) regresses in men. Cloacal membrane (D) is not associated with adenocarcinoma. The nephrogenic cord (E) makes kidneys.

Question 5

A 19-year-old phenotypic female is evaluated for primary amenorrhea. Karyotype is 46,XX. MRI shows absent uterus, absent cervix, absent upper 2/3 of the vagina, and a short blind-ending vagina. Ovaries and external genitalia are normal. Renal ultrasound reveals a unilateral absent kidney. The best explanation for the combination of genital and renal findings is:

A. Androgen receptor mutation (CAIS)

B. Failure of paramesonephric duct development (Müllerian agenesis)

C. 21-hydroxylase deficiency

D. 5α-reductase deficiency

E. Swyer syndrome (46,XY gonadal dysgenesis)

✓ Correct: B — Mayer–Rokitansky–Küster–Hauser (MRKH) syndrome = Müllerian agenesis.

In MRKH, the paramesonephric ducts fail to form or canalize → no fallopian tubes, no uterus, no cervix, and no upper 2/3 of the vagina. The lower 1/3 (UG-sinus derived) is present but ends blindly. Ovaries (gonads, not ducts) are normal, so estrogen and pubertal breast development are normal. Because Müllerian development depends on the mesonephric duct as a guide, concurrent mesonephric defects produce ipsilateral renal anomalies (agenesis or ectopic kidney) in ~30–40% of MRKH patients. Karyotype 46,XX distinguishes MRKH from CAIS (46,XY; no uterus because MIS works normally). Testosterone is normal in MRKH.

Question 6

A 3-month-old boy is taken to surgery for bilateral cryptorchidism. In the pelvis, the surgeon unexpectedly identifies a small uterus and two fallopian tubes in addition to the two undescended testes. Karyotype is 46,XY; testosterone and DHT are normal. The most likely defective embryologic signal is:

A. Leydig cell testosterone secretion

B. 5α-reductase activity in the external genitalia

C. Sertoli cell secretion of Müllerian Inhibiting Substance

D. Androgen receptor signaling

E. GDNF-RET signaling during kidney induction

✓ Correct: C — Persistent Müllerian Duct Syndrome (PMDS): defective MIS (AMH) from Sertoli cells.

The patient has intact testes, normal testosterone (Leydig), and normal DHT (5α-reductase) — which explains the male external genitalia and internal Wolffian derivatives (vas deferens, epididymis). However, Müllerian-derived structures are present, indicating that either MIS (encoded by AMH) is deficient or its type II receptor is nonfunctional. Clinical tie-in: the retained Müllerian structures often tether the testes, causing cryptorchidism. Contrast with CAIS (D; androgen receptor broken — no Wolffian or Müllerian) and 5α-reductase (B; female-appearing external genitalia at birth).

LO 3 — Genital Differentiation (Q7–Q9)

Question 7

A researcher selectively knocks out expression of the androgen receptor in a developing 46,XY embryo while leaving all other hormonal pathways intact. Which of the following best describes the predicted external and internal phenotype at birth?

A. Male internal ducts, male external genitalia

B. Female internal ducts, female external genitalia

C. Neither Wolffian nor Müllerian ducts; female external genitalia

D. Male internal ducts, female external genitalia

E. Female internal ducts, ambiguous external genitalia

✓ Correct: C — Complete Androgen Insensitivity: no Wolffian (T can't signal), no Müllerian (MIS works), female external phenotype (no DHT effect).

The androgen receptor is the single relay for both testosterone (acts on Wolffian duct) and DHT (acts on external genitalia + prostate). Knocking out AR silences both T and DHT effects. Sertoli cells still make MIS, which causes Müllerian regression — so there's no uterus or upper vagina either. External genitalia default to female because there is no functional DHT signaling. Clinical tie-in: CAIS patients are phenotypic females with bilateral testes (often inguinal/abdominal) and a short blind vagina; breast development occurs at puberty because aromatase converts testosterone to estradiol.

Question 8

A term infant is born with ambiguous genitalia, including an enlarged phallic structure and partially fused labioscrotal folds. Karyotype returns 46,XX. Which of the following hormones, secreted by the fetus itself, is most likely responsible for the virilized external phenotype?

A. Anti-Müllerian hormone (MIS)

B. Estradiol

C. Dihydrotestosterone (DHT)

D. Aldosterone

E. Cortisol

✓ Correct: C — DHT, synthesized from adrenal androgens via 5α-reductase, virilizes the external genitalia.

In 46,XX first-trimester androgen excess (most commonly 21-hydroxylase CAH, but also 11β-hydroxylase CAH or exogenous sources), the fetal adrenal makes large amounts of androstenedione / testosterone, which is converted to DHT locally in the genital skin. DHT drives labioscrotal fusion, clitoromegaly, and a common urogenital sinus. MIS (A) regresses Müllerian ducts but doesn't virilize. Estradiol (B) doesn't cause virilization. Aldosterone (D) / cortisol (E) aren't androgens. Timing matters — first-trimester exposure produces fusion; third-trimester exposure causes clitoromegaly alone.

Question 9

A 15-year-old with a 46,XY karyotype presents with primary amenorrhea, absent breast development, and Tanner I pubic hair. Labs reveal FSH 70 mIU/mL, LH 45 mIU/mL, testosterone < 20 ng/dL, estradiol < 10 pg/mL. MRI shows a small uterus and bilateral streak gonads. Which of the following best explains this presentation?

A. Klinefelter syndrome (47,XXY)

B. Complete Androgen Insensitivity Syndrome

C. 5α-reductase deficiency

D. Swyer syndrome (46,XY gonadal dysgenesis)

E. Müllerian agenesis (MRKH)

✓ Correct: D — Swyer syndrome: 46,XY gonadal dysgenesis from SRY loss-of-function or deletion.

Without SRY, the bipotential gonad cannot become a testis → streak gonads form instead. No Sertoli cells → no MIS → Müllerian ducts persist (small uterus, tubes, upper vagina). No Leydig cells → no testosterone → Wolffian ducts regress and external genitalia default to female. Because there is no negative feedback from gonadal steroids, gonadotropins are elevated (hypergonadotropic hypogonadism). Contrast with CAIS (B): 46,XY, no uterus (MIS works), high-normal testosterone, breasts develop via aromatase. Swyer patients need estrogen replacement for puberty and gonadectomy (dysgenic gonads → ↑ risk of gonadoblastoma).

LO 4 — Urinary & Genital Anomalies (Q10–Q13)

Question 10

A neonate is born at 36 weeks gestation with flattened facies, clubbed feet, low-set ears, and respiratory failure in the delivery room. Ultrasound done during pregnancy showed severe oligohydramnios and the fetal bladder could not be visualized. Autopsy is requested. Which of the following is the most likely direct cause of death?

A. Renal failure

B. Pulmonary hypoplasia

C. Congenital heart disease

D. Hyperkalemia from acute tubular necrosis

E. Sepsis from urinary tract infection

✓ Correct: B — Pulmonary hypoplasia from intrauterine oligohydramnios (Potter sequence).

After the second trimester, amniotic fluid comes primarily from fetal urine. Bilateral renal agenesis or severe obstructive uropathy prevents this → oligohydramnios → mechanical compression of the fetus (flat facies, clubbed feet, limb deformities) and — critically — failure of lung distension. The lungs require amniotic fluid movement and fetal breathing to develop normal alveolar architecture. Pulmonary hypoplasia causes fatal respiratory failure at birth — the placenta handled waste during gestation, so renal failure (A) is not the killer. This is the classic Potter sequence.

Question 11

A 6-year-old girl presents with continuous urinary dampness requiring pads despite normal voiding every 2–3 hours. Exam is unremarkable except for mild perineal dermatitis. Renal ultrasound reveals a duplex collecting system on the left kidney. Which additional finding is most likely explaining her continuous incontinence?

A. The upper-pole ureter inserts into the urethra distal to the external sphincter

B. The lower-pole ureter is refluxing urine back into the kidney

C. The upper-pole ureter inserts at the trigone with vesicoureteral reflux

D. Bilateral renal agenesis with oligohydramnios

E. A patent urachus connecting bladder to umbilicus

✓ Correct: A — Ectopic upper-pole ureter inserting below the external urethral sphincter.

By the Weigert-Meyer rule, in a duplex kidney the upper-pole ureter inserts inferiorly and medially (often ectopically) while the lower-pole ureter inserts normally at the trigone. In females, an ectopic ureter can open below the external urethral sphincter (urethra distal to sphincter, vestibule, or vagina), bypassing continence — producing continuous dribbling despite an otherwise normal voiding pattern from the intact ureter. VUR (B/C) causes recurrent UTIs but not continuous incontinence. Bilateral renal agenesis (D) would not be compatible with a 6-year-old. Patent urachus (E) would drain from the umbilicus.

Question 12

An 18-month-old boy undergoes surgery for a right-sided undescended testis found in the inguinal canal. Which of the following is true regarding his long-term risk and the purpose of early intervention?

A. Testosterone production from the affected testis is severely impaired

B. Early orchidopexy substantially reduces future risk of seminoma

C. Delaying surgery until age 10 has no impact on fertility

D. The contralateral descended testis is at increased risk of torsion

E. Elevated testosterone levels explain the cryptorchidism

✓ Correct: B — Early orchidopexy reduces (though does not eliminate) the risk of germ-cell tumor (classically seminoma).

An undescended testis sits in the warmer abdominal/inguinal environment, which damages heat-sensitive seminiferous tubules — reflected in ↓ inhibin B and ↑ FSH. Leydig cells are heat-resistant, so testosterone is usually normal (A incorrect). The longer the testis remains undescended, the greater the risk of seminoma (most common germ cell tumor in abdominal testis). Orchidopexy before age 1 (ideally) maximizes preservation of fertility and reduces malignancy risk, though does not normalize it completely. The ipsilateral testis — not the contralateral — is at ↑ torsion risk (D incorrect). Cryptorchidism is associated with low, not elevated, androgen axis activity (E incorrect).

Question 13

A newborn male is examined and the urethral meatus is found on the ventral surface of the penile shaft midway between the glans and the scrotum. Which of the following is the most appropriate next step in management?

A. Immediate circumcision to reduce UTI risk

B. Defer circumcision; refer to pediatric urology for planned urethroplasty

C. Order karyotype to assess for disorders of sexual differentiation

D. Begin testosterone therapy to promote urethral fold fusion

E. Obtain a brain MRI to rule out Kallmann syndrome

✓ Correct: B — Defer circumcision; the foreskin is preserved for use in urethroplasty.

The finding is penile hypospadias — failure of the urogenital (urethral) folds to fuse ventrally, driven by insufficient DHT effect during fetal development. Definitive repair (urethroplasty) is typically performed between 6 and 18 months and often requires the foreskin as a tissue graft. Early circumcision destroys this reconstruction option. Routine karyotype (C) isn't indicated for isolated mild hypospadias, but is warranted if cryptorchidism, ambiguous genitalia, or bilateral non-palpable testes are present (to rule out virilized 46,XX CAH). Testosterone therapy (D) is not standard and would not reverse the structural defect. Brain MRI (E) is not indicated — Kallmann involves hypothalamic GnRH deficiency and anosmia.

LO 5 — Disorders of Sex Development (Q14–Q18)

Question 14

A 10-day-old infant is brought to the ED with vomiting, lethargy, and failure to thrive. Exam reveals an enlarged clitoris with partially fused labioscrotal folds. Labs: Na 121 mEq/L, K 6.7 mEq/L, glucose 42 mg/dL, 17-hydroxyprogesterone markedly elevated. Which of the following medications would most directly address both the cortisol deficiency and the hormonal shunting toward androgens?

A. Fludrocortisone

B. Hydrocortisone

C. Spironolactone

D. Dexamethasone suppression test dose

E. Testosterone

✓ Correct: B — Hydrocortisone replaces cortisol AND suppresses ACTH, which reduces precursor shunting into the androgen pathway.

In 21-hydroxylase deficiency (classic salt-wasting CAH), cortisol production is impaired. Loss of negative feedback causes ↑ ACTH, which drives adrenal hyperplasia and push more precursors through the only pathway still open — androgens. Hydrocortisone replaces cortisol and suppresses ACTH, reducing shunting. Fludrocortisone (A) is also needed to replace aldosterone and correct salt-wasting, but it does not address cortisol or androgen shunting. Spironolactone (C) blocks aldosterone — opposite of what we want. Dexamethasone suppression (D) is diagnostic, not therapeutic. Testosterone (E) is dangerous — the patient already has androgen excess.

Question 15

A 16-year-old 46,XY is brought to the clinic by her parents because she has not started menstruating. She is tall for age, has Tanner IV breast development, sparse pubic hair, and no uterus on pelvic imaging. Bilateral inguinal masses are palpable. Which of the following is the most appropriate long-term management plan?

A. Immediate gonadectomy and testosterone replacement

B. Gonadectomy after completion of puberty; raise as female; estrogen replacement

C. Orchidopexy and raise as male

D. Hydrocortisone and fludrocortisone therapy

E. Growth hormone and fludrocortisone

✓ Correct: B — Complete Androgen Insensitivity Syndrome: gonadectomy AFTER puberty, raise as female, estrogen replacement.

The clinical pattern (46,XY, female phenotype with breast development, sparse pubic hair, absent uterus, and inguinal testes) is classic CAIS. Testes allow pubertal feminization via aromatase converting testosterone to estradiol → breast development. Because retained undescended testes have ↑ malignancy risk (germ-cell tumor / gonadoblastoma), they are removed after puberty completes natural feminization. Estrogen replacement is then lifelong. Pre-pubertal gonadectomy (A) loses pubertal feminization benefit. Orchidopexy (C) and masculinization is not appropriate — the androgen receptor cannot respond to testosterone. CAH treatments (D, E) are not the issue here.

Question 16

A newborn 46,XY has ambiguous external genitalia with a small phallus and penoscrotal hypospadias; internal imaging shows normal epididymis, vas deferens, and seminal vesicles. At age 12, dramatic virilization occurs — voice deepens, muscle mass increases, and the phallus enlarges. Labs show testosterone 650 ng/dL, DHT 15 ng/dL (ref 30–85). Which enzyme is deficient?

A. 21-hydroxylase

B. 11β-hydroxylase

C. 17α-hydroxylase

D. 5α-reductase

E. Aromatase

✓ Correct: D — 5α-reductase deficiency.

The Wolffian-derived internal ducts (SEED) are normal because they depend on testosterone directly — and testosterone is normal. The external genitalia require DHT, which is deficient → ambiguous/female-appearing at birth with penoscrotal hypospadias. At puberty, the massive testosterone surge partially drives virilization through residual T action and alternative DHT-generating pathways ("female at birth, male at puberty"). Hallmark lab: ↑ testosterone-to-DHT ratio. Not CAH (A/B/C — those have abnormal adrenal steroids and ambiguous findings at birth in different patterns). Aromatase deficiency (E) would cause maternal + fetal virilization and no estrogens at puberty (different presentation).

Question 17

A 24-year-old man presents with infertility. Exam reveals tall stature, long extremities, and small, firm testes bilaterally. He also notes mild gynecomastia. Labs: FSH 42 mIU/mL (high), LH 18 mIU/mL (high), testosterone 250 ng/dL (low-normal), estradiol 55 pg/mL (high), inhibin B low. Karyotype is pending. What is the most likely karyotype?

A. 45,XO

B. 46,XY with SRY deletion

C. 46,XX with SRY translocation

D. 47,XXY

E. 47,XYY

✓ Correct: D — Klinefelter syndrome (47,XXY).

Classic Klinefelter triad: tall stature, small firm testes, and infertility. Seminiferous tubule dysgenesis → ↓ inhibin B → ↑ FSH; Leydig cell impairment → low-normal testosterone and ↑ LH. Elevated estradiol from aromatization of residual testosterone (and decreased SHBG) causes gynecomastia. 45,XO (A) is Turner — short female phenotype with primary amenorrhea. SRY deletion (B) causes Swyer syndrome. SRY translocation (C) = 46,XX male — small testes but short stature. 47,XYY (E) is associated with tall stature and mild behavioral features, but testicular size and fertility are usually normal. Klinefelter is the most common cause of male infertility from a chromosomal etiology.

Question 18

A 12-year-old girl presents with short stature and primary amenorrhea. Exam reveals a webbed neck, shield chest with widely spaced nipples, and a wide carrying angle. Echocardiogram shows a bicuspid aortic valve; renal ultrasound shows a horseshoe kidney. Which of the following hormone patterns is most consistent with this diagnosis?

A. ↑ FSH, ↑ LH, ↓ estradiol

B. ↓ FSH, ↓ LH, ↓ estradiol (hypothalamic)

C. ↑ FSH, ↑ LH, ↑ estradiol

D. ↑ 17-OH progesterone, ↓ Na, ↑ K

E. Normal FSH/LH, high prolactin

✓ Correct: A — Hypergonadotropic hypogonadism: streak ovaries → ↓ estradiol → loss of feedback → ↑ FSH and ↑ LH.

Turner syndrome (45,XO) features accelerated ovarian follicle atresia → streak gonads → no estrogen synthesis → primary amenorrhea and failure of secondary sex characteristics. Loss of estrogen negative feedback on the pituitary causes hypergonadotropic hypogonadism (↑↑ FSH, ↑ LH, ↓ estradiol). Classic associations: bicuspid aortic valve (most common cardiac anomaly), coarctation, and horseshoe kidney — all shown here. Management: growth hormone for height, estrogen replacement at puberty, and close cardiac follow-up (↑ aortic dissection risk). B is hypothalamic hypogonadism (e.g., Kallmann) — but Turner is primary ovarian failure. D is 21-OH CAH. E suggests prolactinoma.